Question

Given a
12
​
=37,d=3, find a and S
12
​

Answer 1

Answer:

a12=37,d=3

a12=a+(12−1)d

37=a+(11×3)

37−33=a

a=4

s12=212[2a+(12−1)3]

s12=6[8+33]

s12=246

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Answer 2

Answer:

37=a+3(12−1)=a+33

⇒a=37−33=4

S

12

=

2

12

(4+37)=246