given a=2, s10==125 find d and a10
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Answer:
a = 2
s10 = 125
n = 10
s10= 10/2[2(2)+(9)d]
125 = 5(4+9d)
25 = 4+9d
9d = 21
d = 21/9
d = 7/3
a10 = 2+(9)(7/3)
= 2+21
= 23
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