Question

Given A= 2i+4j-5k the magnitude of vector A is​

Answer 1

Answer:

Given, vector A = 2i + 4j - 5k.

Here, i, j and k are unit vectors along positive X, Y and Z axes respectively.

So, |A| = |√[(2^2) + (4^2) + {(-5)^2]| = |√45| = √45

So, unit vector along A = (A cap) = (A / |A|)

= (1 / √45) * (2i + 4j - 5k)

≈ 0.149 * (2i + 4j - 5k)

≈ (0.298i + 0.596j - 0.745k).

Explanation:

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Answer 2

Given,

The vector is A = 2i+4j-5k

To find,

The magnitude of the given vector.

Solution,

We can simply solve this mathematical problem by using the following mathematical process.

The magnitude of a vector is actually the length of that vector.

So, by applying the necessary mathematical formula, we get that,

|A| = √(2)²+(4)²+(-5)² = √(4+16+25) = √45 = √(5×9) = 3√5

(This value of |A| will be considered as the magnitude of the given vector.)

Hence, the magnitude of the given vector is 3√5