given a=5,d=3, an =50, find n and sn
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an= a+(n-1)d
50=5+(n-1)3
50-5=3n-3
45+3=3n
48=3n
n=48/3
n=16
now sn=n/2(2a+(n-1)d
=16/2(2*5+(16-1)3
=8(10+45)
=8*55
sn=440
50=5+(n-1)3
50-5=3n-3
45+3=3n
48=3n
n=48/3
n=16
now sn=n/2(2a+(n-1)d
=16/2(2*5+(16-1)3
=8(10+45)
=8*55
sn=440
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