given a=5,d=3, an=50,find n and sn
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14
Given a = 5, d = 3 an = 50.
We know that an = a + (n-1) * d
50 = 5 + (n-1) * 3
50 = 5 + 3n - 3
50 = 2 + 3n
48 = 3n
n = 16.
We know that Sum of n terms = n/2(a + an)
= 16/2(5 + 50)
= 440.
We know that an = a + (n-1) * d
50 = 5 + (n-1) * 3
50 = 5 + 3n - 3
50 = 2 + 3n
48 = 3n
n = 16.
We know that Sum of n terms = n/2(a + an)
= 16/2(5 + 50)
= 440.
Answered by
12
given,
a=5,d=3, an=50
an =a+((n-1)d
50= 5+3n -3
48= 3n
n= 16
sn= n/2{2a+(n-1)d}
= 16/2({ 2(5)+(16-1)3
= 8(10+15×3)
=8(55)
= 440
a=5,d=3, an=50
an =a+((n-1)d
50= 5+3n -3
48= 3n
n= 16
sn= n/2{2a+(n-1)d}
= 16/2({ 2(5)+(16-1)3
= 8(10+15×3)
=8(55)
= 440
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