Question

Given A=60° and B =30°, prove that : cos (A-B) =cos A cos B+sin A sin B

Answer 1

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Answer 2

Answer:-

From LHS cos(A-B) = cos ( 60°-30°) = cos30° =√3/2

From RHS

=cosA * cosB + sinA * sinB

= cos60° * cos30° + sin60° sin30°

= 1/2 * √3/2 + √3/2 * 1/2

= √3/4 + √3/4 = 2√3/4 = √3/2

Hence , Here Proved , lHS = Proved ✔