given A = 60° and B = 30°, prove that:
sin (A + B) = sin A cos B + cos A sin B
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Answer:
sin(60+30) = sin 60.cos30 + cos60.sin30
sin90 =√3/2 × √3/2 + 1/2 × 1/2
(because sin60 = √3/2. cos30 = √3/2. cos60 =1/2. sin30 = 1/2 )
1 = 3/4 + 1/4 (sin 90 = 1)
1 = 4/4
1=1
hence proved
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