given a = 7, a13 = 35. find d and S13
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Answered by
1
Answer:
This is the answer:
Step-by-step explanation:
Hello Friend
as you have given
a=7
a¹³ = 35 it means no of terms = 13
so n = 13.
we know
aⁿ = a+(n-1)d
so put the values .----
35 = 7 +(13-1)d
28 = 12d
so
d = 28/12 => 7/3
Now sⁿ = n/2(a+aⁿ)
hence we get
sⁿ = 13/2(7+35)
=> 13/2(42)
=>21×13
=> 273
.
Answered by
1
Answer:
a=7
a13=35
since n=13
now,
an=a+(n-1)d
35=7+(13-1)d
35-7=12d
28=12d
28/12=d
d=7/3
now we know that
sn=n/2(a+an)
hence we get
s13= 13/2(7+35)
s13=13/2*42
s13=273
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