Question

Given : a = 9.00 +- 0.05, b = 0.0356 +- 0.0002, c = 15300 +- 100, d = 62000 +- 500. Find the maximum value of absolute error in a + b + c + d
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Answer 1

Answer:

600.0502

Step-by-step explanation:

Maximum value of absolute error is the sum of individual errors. So, if s=a+b+c+d then Δs=Δa+Δb+Δc+Δd=0.05+0.0002+100+500=600.0502.

Answer 2

Answer:

The maximum value of absolute error in a + b + c + d is 600.0502.

Step-by-step Explanation:

Given,

a = 9.00 ± 0.05,

b = 0.0356 ± 0.0002,

c = 15300 ± 100,

d = 62000 ± 500.

To find the maximum value of absolute error in a + b + c + d, we need to calculate the sum and add the absolute errors of each term.

Sum = a + b + c + d

= (9.00 + 0.0356 + 15300 + 62000)

= 77309.0356

Absolute error of a = 0.05

Absolute error of b = 0.0002

Absolute error of c = 100

Absolute error of d = 500

Maximum value of absolute error in (a + b + c + d) = absolute error of a + absolute error of b + absolute error of c + absolute error of d (sum of the respective absolute errors)

= (0.05 + 0.0002 + 100 + 500)

= 600.0502

Therefore, the maximum value of absolute error in a + b + c + d is 600.0502.

Keywords: absolute error, maximum value, sum.

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