Given a ∆ABD in which AB=AD and AC bisects BD prove that :. ∆ABC=~∆ADC
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Step-by-step explanation:
IN ΔABC &ΔABD
AB=AD(GIVEN)
BC=CD(As AC bisect BD)
AC=AC(COMMON)
SO ΔABC=~ΔABD
By SSS CRITERIA(RULE)
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