Given |A| +|B| + |C| = 0, |B| = |C| and |C| = √2|A|. What is the angle between A vector and B vector?
Answers
Answered by
0
Answer:
The angle α which the resultant R makes with A is given by
tanα=
A+Bcosθ
Bsinθ
or
cos(θ/2)
sin(θ/2)
=
A+Bcosθ
2Bsin(θ/2)cos(θ/2)
which gives A+Bcosθ=2Bcos
2
(
2
θ
)
or A+B[2cos
2
(
2
θ
)−1]=2Bcos
2
(
2
θ
)
A=B
Similar questions