Question

Given a, b, c, d, e are natural numbers such that a + b + b + c + c + d+ d + e =4021 and a+b+c+d+e=11063. then the numerical value of (a-d) is? ​

Answer 1

Answer:

a=C−2D

b=C−D

c=C

d=C+D

e=C+2D

Then,

a+b+c+d+e=5C=α

3

....(i)

b+c+d=3C=β

2

=675

c=C=675