Given: A ≅ B, CD is an angle bisector of ACB
Prove: AC ≅ BC
Provide the reasons
Attachments:
Answers
Answered by
2
Step-by-step explanation:
if CD s the bisector of angle acb , then angle acd=angle bcd. angle a =angle b. so definitely angle cda=angle bdc.
so in triangles, acd and bcd,
angle acd=angle bcd
angle adc=angle bdc
cd=DC which is a common side.
so those triangles are congruent to each other.
so ac has to be equal to bc because
CORRESPONDING PARTS OF CONGRUENT TRIANGLES ARE EQUAL AND BC CORRESPONDS TO AC. THUS THEY ARE EQUAL.
HENCE, PROVED.
PLZ MARK AS BRAINLIEST
Similar questions