◈ Given ◈
A car moves with a speed of 40 km/h for 15 minutes and then with a speed of 60km/h for the next 15 minute.
◈ To find ◈
Total distance covered by car
◈ Solution ◈
\begin{gathered}\\\qquad\quad{\underline{\bf{\red{First\: condition}}}}\\\end{gathered}Firstcondition
A car moves with a speed of 40 km/h for 15 minutes
\begin{gathered}\\\bullet\:\sf Speed\:of \: a \: car = 40km/h\end{gathered}∙Speedofacar=40km/h
\begin{gathered}\bullet\:\sf Time = 15 min\\\end{gathered}∙Time=15min
Note :
1 hour = 60 min
Time = 15/60 = 1/4 hour
\begin{gathered}\\\qquad\quad{\blue{\boxed{\sf{\blue{Speed=\dfrac{Distance}{Time}}}}}}\\\\\end{gathered}Speed=TimeDistance
\begin{gathered}\implies\sf Distance=Speed\times time \\\\\end{gathered}⟹Distance=Speed×time
\begin{gathered}\implies\sf D_1 = 40 \times \dfrac{1}{4} \\\\\end{gathered}⟹D1=40×41
\begin{gathered}\implies\sf D_1 = 10km \\\end{gathered}⟹D1=10km
\therefore{\underline{\boxed{\tt{Distance\:travelled\: i.e \: \bf 10km}}}}∴Distancetravelledi.e10km
\: ____________________________________________
\begin{gathered}\\\qquad\quad{\underline{\bf{\red{Second\: condition}}}}\\\end{gathered}Secondcondition
A car moves with a speed of 60km/h for the next 15 minute.
\begin{gathered}\\\bullet\:\sf Speed\:of \: a \: car = 60km/h\end{gathered}∙Speedofacar=60km/h
\begin{gathered}\bullet\:\sf Time = 15 min\\\end{gathered}∙Time=15min
Convert min into hour
\begin{gathered}\implies\sf Distance=Speed\times time \\\\\end{gathered}⟹Distance=Speed×time
\begin{gathered}\implies\sf D_2 = 60 \times \dfrac{1}{4} \\\\\end{gathered}⟹D2=60×41
\begin{gathered}\implies\sf D_2 = 15km \\\end{gathered}⟹D2=15km
\therefore{\underline{\boxed{\tt{Distance\:travelled\: i.e \: \bf 15km}}}}∴Distancetravelledi.e15km
\: ____________________________________________
\begin{gathered}{\large\ast}\:{\underline{\bf{\purple{Total\:distance\: travelled}}}}\:{\large\ast}\\\\\end{gathered}∗Totaldistancetravelled∗
\begin{gathered}\implies\sf D_1 + D_2 \\\\\end{gathered}⟹D1+D2
\begin{gathered}\implies\sf 10 + 15 \\\\\end{gathered}⟹10+15
\begin{gathered}\implies\sf 25km \\\end{gathered}⟹25km
\therefore{\underline{\boxed{\tt{Total \: distance\:travelled\: by \: a\: car =\bf 25km}}}}∴Totaldistancetravelledbyacar=25km
\: ____________________________________________
Answers
Answered by
6
Answer:
Speed of the car in first 15 minutes
=40km/h
distance=speed x time
1h=60minutes
=15/60
distance covered=40x15/60=10km
thus,10km in first 15 minutes
speed of the car in next 15 minutes=60km/h
distance=speed x time
1h=60minutes
15/60
distance covered=60x15/60=15km
thus,15km in next 15 minutes
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