Question

Given a channel with an intended capacity of 20 Mbps, the bandwidth of the channel is 3 MHz. What signal-to-noise ratio is required to achieve this capacity​

Answer 1

Given  :  a channel with an intended capacity of 20 Mbps,

the bandwidth of the channel is 3 MHz.

To Find :  signal-to-noise ratio   to achieve this capacity​

Solution:

C = B log₂ ( 1 + SNR)

C = capacity = 20 Mbps = 20 x 10⁶ bps

B = Bandwidth = 3 Mhz  = 3 x 10⁶ Hz

SNR = signal-to-noise ratio

20 x 10⁶   =  3 x 10⁶  log₂ ( 1 + SNR)

=> 20/3  = log₂ ( 1 + SNR)

=> 101.6 = 1 + SNR

=>  100.6 = SNR

SNR ≥ 100.6

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Answer 2

Answer:

Step-by-step explanation: