given a channel with an intended capacity of 20Mbs. the bandwidth of this channel is 3MHz.what is (S/N) ratio required in order to achieve this capacity
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Given : a channel with an intended capacity of 20 Mbps,
the bandwidth of the channel is 3 MHz.
To Find : signal-to-noise ratio to achieve this capacity
Solution:
C = B log₂ ( 1 + SNR)
C = capacity = 20 Mbps = 20 x 10⁶ bps
B = Bandwidth = 3 Mhz = 3 x 10⁶ Hz
SNR = signal-to-noise ratio
20 x 10⁶ = 3 x 10⁶ log₂ ( 1 + SNR)
=> 20/3 = log₂ ( 1 + SNR)
=> 101.6 = 1 + SNR
=> 100.6 = SNR
SNR ≥ 100.6
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