Question

Given a chord AB of length 5 cm, of a circle with centre O. OL is perpendicular to chord AB and OL=4 cm. OM is perpendicular to chord CD such that OM=4 cm. Then CM is equal to



a. 4 cm

b. 2.5 cm

c. 5 cm

d. 3 cm

​

Answer 1

Answer:

b) 2.5 cm

Step-by-step explanation:

chord CD = AB = 5 cm

CM = CD/2 (A perpendicular from the centre to the chord bisects the chord.)

CM = 5/2= 2.5 cm