Question

given: a circle with centre o. angle BAC = 62° . compute the measure of angle BOC​

Answer 1

Answer:

Tangent is perpendicular to radius at point of contact.

So, ∠ABO=∠ACO=90∘

In a quadrilateral, the sum of the angles is 360∘. 

∠BAC+∠BOC+∠ABO+∠ACO=360∘

∴∠BAC+∠BOC=180∘

                      ∠BOC=180∘−40∘

                      ∠BOC=140∘