given: a circle with centre P. seg AC is a diameter point B is outside the circle.
to find type of angle ABC. solution: let AB intersects circle at point Q.
Draw seg CQ.
Answers
Given : a circle with centre P. seg AC is a diameter
point B is outside the circle.
To find : type of angle ABC.
Solution:
Join AB intersecting circle at point D
Jon CD
in ΔADC , AC is diameter
Hence ∠ADC = 90°
in ΔCDB
∠ADC = ∠DBC + ∠DCB ( Exterior angle of triangle = Sum of interior angles )
∠DBC = ∠ABC (∵ ADB is straight line)
∠ADC = ∠ABC + ∠DCB
=> 90° = ∠ABC + ∠DCB
=> ∠ABC = 90° - ∠DCB
=> ∠ABC < 90°
Hence ∠ABC is acute angle
type of angle ABC. is Acute
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