Question

Given a circle with measures of (C, d, and r) and a circle with measures of (C', d', and r'), what is r' if C C' = 3.0 and d = 12.0? A) 2 B) 4 C) 8 D) 12

Answer 1

2

Step-by-step explanation:

two measure two circle

Answer 2

A) 2

The value of r' is 2 units.

Explanation:

The formula for circumference of the circle:

$C=2\pi r$ , where r = radius of the circle.             (1)

or

$C=\pi d$ , where diameter of the circle.                  (2)

Given a circle with measures of (C, d, and r) .

d= 12.0 units

Then, the circumference of the circle 1 : $C=12\pi$                 (By 2)

The other circle has measures (C', d', and r'), the circumference of circle will be :

$C' = 2\pi r'$                                          (By 1)

The ratio of circumferences of circle 1 and circle 2 will be :-

$\dfrac{C}{C'}=\dfrac{12\pi}{2\pi r'}$

$\Rightarrow\ \dfrac{C}{C'}=\dfrac{6}{r'}$                                     (3)

Since,  $\dfrac{C}{C'}=3$                       ( given )              (4)

from (3) and (4)

$\dfrac{6}{r'}=3$

$\Rightarrow\ r'=\dfrac{6}{3}=2$

Hence, the value of r' is 2 units.

Therefore , the correct option is A) 2

# Learn more :

Given a circle with measures of (C, d, and r) and a circle with measures of (C', d', and r'), find r' if

C

C'

= 0.75 and d = 3.0.

A) 2

B) 3

C) 4

D) 8

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