Question

Given a circle with two intersecting chords, how
long is chord AB if chord CD bisects chord AB
at point o, and CO = 5 and OD = 3?​

Answer 1

Answer:

AO*OB = CO*OD

AO*OB = 3*5

AO*OB = 15

only possible values with natural number are (1,15) & (3,5)

so,

length of chord AB can be = 16 or 8 ...

(Mark as brainlist)

Answer 2

Answer:

yes

Step-by-step explanation:

Refer the attachment.