Question

Given :-

A closed cylindrical tank of radius 3.5 m and height 2 m is made from a sheet of metal.

To Find :-

How much sheet of metal is required.

Formula Used :-

{\red{\boxed{\large{\bold{T.S.A\: of\: cylinder\: =\: 2{\pi}r(r + h)}}}}}T.S.Aofcylinder=2πr(r+h)​
where,

r = Radius

h = Height

Solution :-

Given :

Radius = 3.5 m

Height = 2 m

According to the question by using the formula we get,
⇒ \sf T.S.A =\: 2 \times \dfrac{22}{7} \times 3.5(3.5 + 2)T.S.A=2×722​×3.5(3.5+2)
⇒ \sf T.S.A =\: 2 \times \dfrac{22}{7} \times 3.5(5.5)T.S.A=2×722​×3.5(5.5)
⇒ \sf T.S.A =\: 2 \times \dfrac{22}{7} \times 3.5 \times 5.5T.S.A=2×722​×3.5×5.5
⇒ \sf T.S.A =\: 2 \times \dfrac{22}{7} \times 19.25T.S.A=2×722​×19.25
⇒ \sf T.S.A =\: 2 \times 60.5T.S.A=2×60.5
➠ \sf\bold{\purple{T.S.A =\: 121\: {m}^{2}}}T.S.A=121m2
\therefore∴ 121 m² of sheet of metal is required.
​

Answer 1

Explanation:

times 19.25T.S.A=2×722×19.25

⇒ \sf T.S.A =\: 2 \times 60.5T.S.A=2×60.5

➠ \sf\bold{\purple{T.S.A =\: 121\: {m}^{2}}}T.S.A=121m2

\therefore∴ 121 m² of sheet of metal is required.