Question

given a coil having a resistance of 10 ohms and inductance of 0.1 H is connected in parallel with a capacitor of 10 micro farad across 200V, 50Hz supply. find the current through the capacitor, total current and power factor​

Answer 1

Answer:

RMS value of applied voltage = 200 V

Impedance of a capacitor is given by:

X

C

=

2πfC

1

Hence, rms current through it is:

I=

X

C

V

I=200×2×π×50×10×10

−6

I=0.2π A

Peak current, I

max

=

2

I

=0.628

2

A