Question

Given a container of oxygen gas with an initial volume of 280 litres and temperature of 30°C, calculate the volume if the temperature is changed to -2.0°C at constant pressure.​

Answer 1

Given :

• Initial temperature( T₁ ) = 30°C
• Initial volume ( V₁ ) = 280 litre
• Final temperature (T₂ ) = -2°C.
• Pressure is constant

To find :

Final volume ( V₂ )

SOLUTION :

As pressure is constant, we can use Charles Law , which states that at constant pressure volume is directly proportional to the temperature in Kelvin scale , that is

V ∝ T

T₁ = 30°C

T₁ = 30+ 273

T₁ = 303 K

T₂ = -2°C

T₂ = -2 + 273

T₂ = 271 K

$\sf \implies \: \: \dfrac{V_1}{V_2} = \dfrac{T_1}{T_2} \\ \\ \sf \implies \: \dfrac{280}{V_2} \: = \: \dfrac{303}{271} \\ \\ \sf \implies \: 280 \times \dfrac{271}{303} = \: V_2 \\ \\ \sf \implies \: V_2 \: \: = \dfrac{75880}{303} \\ \\ \sf \implies \: V_2 \: \: = \bold{250.4}$

ANSWER :

Final volume = 250.4 L