Question

Given a cube with side length 2a (a> 0). A point charge q> 0 is located in the center of the cube. Take the known electric field E to a point charge in vacuum as a starting point, and find an expression for the electric field strength E = | E | in the corners of the cube.

Answer 1

Answer:

The Gauss law relates the flux of the electric field thru the Gaussian surface with ... E) Inner charge = 0 mC, Outer charge = 0 mC ... by –1 gives the electric field of the point charge. 2. ( ) q.