Question

given a cuboid with dimensions l=6cm,b=4cm,&h=2cm.finda) total surface area of cuboid b) area of the open cuboid c) area of the four walls of cuboid​

Answer 1

Hope u understood

mark this as brainlist

Answer 2

Step-by-step explanation:

Given,

Cuboid:

Length:6cm

Breadth:4cm

Height:2cm

(a)Total surface area: =2(lb+bh+lh)

                                    =2{ (6)×(4)+ (4)×(2)+ (6)×(2) }

                                    =2{ 24+ 8+ 12 }

                                    =2{44}

                                    =88cm²

(c)Area of four walls: =2(l+b)×h

                                   =2×(6+4)×2

                                   =2×10×2

                                   =40cm²

(b)Area of open cuboid: ( It means the lateral surface area +base area)

  So two formulas should be used: 2(l+b)×h + l×b

 Now as we know the are of four walls is 40cm² let us substitute it.

                                                        =40+ 6×4

                                                        = 40+24

                                                        = 64cm²

 

                                HOPE IT HELPS YOU!!