Question

Given a discount of 20% on a particular
good, a man still paid
still paid $250 What is the
Original price?​

Answer 1

➤ Given :-

Selling price :- ₹ 250

Discount percentage :- 20%

➤ To Find :-

Original price of the given sum

➤ Formula required :-

${\large \tt \dashrightarrow \orange{\boxed{\tt \gray{\dfrac{100}{(100 - Discount \bf\%)} \times Selling \: price}}}}$

➤ Solution :-

Original price :-

${\tt \longrightarrow \dfrac{100}{(100 - 20)} \times 250}$

${\tt \longrightarrow \cancel \dfrac{100}{80} \times 250 = \dfrac{5}{4} \times 250}$

${\tt \longrightarrow \dfrac{5 \times 250}{4} = \dfrac{1250}{4}}$

${\tt \longrightarrow \cancel \dfrac{1250}{4} = \boxed{\tt Rs \: \: 312.5}}$

$\Huge\therefore$ The original price of the given sum is ₹ 312.5.

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$\dashrightarrow$ Some related formulas :-

Profit :- ${\boxed{\tt SP-CP}}$

Loss :- ${\boxed{\tt CP-SP}}$

Profit percentage :- ${\boxed{\tt\dfrac{Profit}{CP} \times 100}}$

Loss percentage :- ${\boxed{\tt\dfrac{Loss}{CP} \times 100}}$

Answer 2

Question:-

1. Given a discount of 20% on a particulargood, a man still paidstill paid $250 What is the Original price?

Given that,

• Discount percent = 20%
• Selling price = $250

To find:-

• The original price on a particular good

Solution:-

$\rm→\dfrac{100}{100-discount\%}×S.P \\ \rm →\dfrac{100}{100-20}×250 \\ \rm→\dfrac{100}{80}×250=\rm\dfrac{5}{4}×250 \\ \rm→5×\dfrac{250}{4}=\dfrac{1250}{4} \\ \rm→\dfrac{1250}{4}={\fbox\red{Rs.312.5}}$

Required answer:-

• 312.5 is the original price of the sum

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