Question

Given A= ICAP + 2 j cap + uk cap and B= 4 ICAP - 2 j cap + 3 k cap product and hence find the component of B along A and also component of A along B in vector form.​

Answer 1

Answer:

AO=i^+2j^uk^

BO=4i^-2j^+3k^

AB=BO-AO

3i^-4j^+(3-u)k^

BA=AO-BO

-3i^+4j^+(u-3)k^