Question

Given A is an acute angle and cosec A = √2, find the value of
2 sin² A + 3 cot² A/
tan² A - COS² A​

Answer 1

Explanation:

Hope it will help you for sure.

Answer 2

Answer:

8

Explanation:

cosecA=√2

{since cosec 45°=√2}

so, cosecA=cosec45°

A=45°

on solving

(2sin²A+3cot²A)/(tan²A-cos²A)

by putting the value of A

(2sin²45°+3cot²A)/(tan²A-cos²A)

[2(1/√2)²+3(1)²)]/[(1)²-(1/√2)²]

(2*1/2+3)/(1-1/2)

(1+3)/[(2-1)/2]

(4)/(1/2)

8