Question

Given a line segment AB, P is a point on the perpendicular bisector of line segment AB, such that AP= 10 cm and AB= 12 cm. Then the distance of point P from line segment AB is ___________

Answer 1

Step-by-step explanation:

As we know , a perpendicular bisector is at 90° on a line

Therefore , we conclude that AP_|_ AB

Hence , A/Q Pythagoras theorem

AP^2 + AB ^2 = BP^2

10^2 + 12 ^2 =BP^2

BP^2 = 144+100

BP= 15.62 (roughly)