Question

Given a number 5 digit number X lets say it can be represented as Newton such that:- 
N, e, w, t, o, n are all unique integers between 5 to 9 
1. (N*10 + e) % 2 =0 
2. (N*100 + e*10 + w) % 3 = 0 
3. (N*1000 + e*100 + w*10 + t) % 4 = 0 
4. (N*10000 + e*1000 + w*100 + t*10 + o) % 5 = 0 
Print the sum of all possible numbers of X
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Answer 1

Answer:

76985

Step-by-step explanation:

e--->6 %2==0

similarly for w. 9

for t. 8

for o 5

are only possible

remaining is 7

so Newton gives only 1sol ie 76985

therefore the sum of all possible no is 76985

Answer 2

Answer:

The sum of all possible numbers of X by calculating the sum of each permutation 750000.

Step-by-step explanation:

From the above question,

They have given :

Since N, e, w, t, o, n are all unique integers between 5 to 9, we have 5! = 120 permutations.

Let us denote X = N * 10000 + e * 1000 + w * 100 + t * 10 + o

The given equation states that the number X can be expressed as a multiple of 2, 3, 4 and 5. This is a form of modular arithmetic, where the modulo (or remainder) of a number is taken after division by a particular number.

The sum of all possible numbers of X can be found by calculating the sum of each permutation of N, e, w, t, o, and n. Since there are 5! = 120 permutations, we can multiply the sum of each permutation by 120 to get the total sum.

We can find the sum of all possible numbers of X by calculating the sum of each permutation:

         120 * (N*10000 + e*1000 + w*100 + t*10 + o)

            = 120 * (5*10000 + 5*1000 + 5*100 + 5*10 + 5)

            = 120 * (62500)

            = 750000

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