Question

Given a number, write a program to reverse the rightmost n digits, n is taken from the first digit of the given
number
Input Format
Input contains an integer value n
Output Format
Print the number after performing partial reverse
Constraints
1 <=N<=10410
Example
32145
First digit of a given number is 3. so the output is 32541​

Answer 1

Answer:

// C++ program to reverse digits of a number

#include <bits/stdc++.h>

using namespace std;

/* Recursive function to reverse digits of num*/

int reversDigits(int num)

{

static int rev_num = 0;

static int base_pos = 1;

if(num > 0)

{

reversDigits(num/10);

rev_num += (num%10)*base_pos;

base_pos *= 10;

}

return rev_num;

}

// Driver Code

int main()

{

int num = 4562;

cout << "Reverse of no. is "

<< reversDigits(num);

return 0;

}

Output:

Reverse of no. is 2654