Given a parallelogram ABCD, with DL I AC
and BM I AC. Prove that
(a) AD = BC (b) ZDAC = ZACB
(c) AADL = ABCM (d) DL = BM
М.
Answers
Hey there !! here is your answer! hope it helped!! please mark as the brainliest answer!!
Answer:
To answer your question, let me tell you the properties of parallelograms.
1. opposite sides are parallel and equal.
2. diagonals bisect each other
3.Opposite angles are equal.
4. Adjacent angles are supplementary(they add up to 180 degrees).
5. Alternate interior angles are equal.
6. sum of angles in a parallelogram is 360 degrees.
7.sum of angles in a triangle is 180 degrees.
Step-by-step explanation:
So, the figure ABCD In your question is a parallelogram.
Using the properties of a parallelogram, let us answer your question:
a) AD=BC ( Since opposite sides are parallel and equal ) .
b) angle DAC= angle ACB(Alternate interior angles are equal)
c)triangle ADL=triangle BCM(sum of angles in a triangle is 180 degrees.)
d) DL = BM(DL II AC)
Hope it helped you !!