Given a pentagon ABCDE. If the quadrilaterals ABCD and BCDE are cyclic, prove that the pentagon is also cyclic
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Answer:
In cyclic quadrilateral BCDE, we have
∠BED+∠BCD=180
0
∠BED+120
0
=180
0
[∠BCD=120
∘
as it is a cyclic pentagon]
Thus, ∠BED=60
0
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