Question

given a polynomial x²-2x+3,then p(1) is​

Answer 1

Answer:

p(x) = x^(2) -2x-3

. <br>

:. (i) p(3) = (3^(2)-2xx3-3) = (9-6-3)=0

<br> and (ii)

p(-1)={(-1)^(2)-2xx(-1)-3}=(1+2-3)=0

. <br> This shows that 3 and -1 are the zeros of the polynomial p(x).

Step-by-step explanation:

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Answer 2

Answer:

2 is the right answer of this question.