given a range [low,high] (both inclusive) , select k number from range (a number can be chosen multiple times ) such that sum those k numbers is even calculate the number of all such permutations As this number can be large
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Answer:
def working():
r1,r2=map(int,input().split())
combo=int(input())
lst=[i for i in range(r1,r2+1)]
print(lst)
a=len(lst)
res=(a**combo)//2
print(res%100000009)
working()
even odd problem
Explanation:
list contains the range of numbers
find total possible pairs based on (combo)[ways]
divide by 2 to get even sum numbers
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