Question

given a rectangle with a fixed perimeter of 24 M if we increase the length of Y1 me the width and area will marry accordingly use the following tables of values to look at how the width and every as the length varies what do you observe write your observation Sydney on notebooks

Answer 1

Answer:

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Step-by-step explanation:

Given, Perimeter of Rectangle= 24 meters

⇒ 2×(l + w) =24

⇒ l + w = 242=12 meters

⇒ w = 12 – l

Therefore, from the table we can now find the width values as length varies

That is, if l = 3 ⇒ w = 12 - 3 = 9

If l =4 ⇒ w = 12 – 4 =8

If l =5 ⇒ w = 12 – 5 =7

If l =6 ⇒ w = 12 – 6 =6

If l =7 ⇒ w = 12 – 7 =5

If l =8 ⇒ w = 12 – 8 =4

If l =9 ⇒ w = 12 – 9 =3

Now, we have both length and width values

Therefore, Area of rectangle = l×w

Where l = length and w = width

From the above values, if l = 3, w = 9 ⇒ Area = 3×9 = 27 m2

If l = 4, w = 8 ⇒ Area = 4×8 = 32 m2

If l = 5, w = 7 ⇒ Area = 5×7 = 35 m2

If l = 6, w = 6 ⇒ Area = 6×6 = 36 m2

If l = 7, w = 5 ⇒ Area = 7×5 = 35 m2

If l = 8, w = 4 ⇒ Area = 8×4 = 32 m2

If l = 9, w = 3 ⇒ Area = 9×3

=27 m2

From the above calculations:

Length (in m) 1 2 3 4 5 6 7 8 9

Width (in m) 11 10 9 8 7 6 5 4 3

Area (in m2 ) 11 20 27 32 35 36 35 32 27