Given a rectangle with a fixed perimeter of 24 meters, if we increase the length by 1m the width and area will vary accordingly. Use the following table of values to look at how the width and area vary as the length varies.What do you observe? Write your observations in your note booksLength(in cm) 1 2 3 4 5 6 7 8 9Width(in cm) 11 10 ……. …….. …….. …….. ……. …… …..Area (in cm²) 11 20 ……. …….. ……. …….. ……. …… ……
Answers
Answer:
Step-by-step explanation:
Perimeter of the rectangle = P = 2(l+b) = 24m
Area = l × b
Adding the length and breadth and multiplying by 2 will give 24.
Thus,
When l = 3, P = 24 2(l+b) = 24 = 2(3+b) b = 9 and A = 27
When l = 4, P = 24 2(l+b) = 24 = 2(4+b) b = 8, and A = 32
When l = 5, P = 24 2(l+b) = 24 = 2(5+b) b = 7, and A = 35
When l = 6, P = 24 2(l+b) = 24 = 2(6+b) b = 6, and A = 36
When l = 7, P = 24 2(l+b) = 24 = 2(7+b) b = 5, and A = 35
When l = 8, P = 24 2(l+b) = 24 = 2(8+b) b = 4, and A = 32
When l = 9, P = 24 2(l+b) = 24 = 2(9+b) b = 3, and A = 27
Therefore, the length and breadth are inversely proportional to each other if the perimeter is kept constant. Area first increases and then decreases with the length.
Step-by-step explanation:
2(l+b)=24
l+b=12
the length and breadth are inversely proportion
