Question

Given a right angled triangle ABC right
angled at B, which tan A = 15/8and
tan c = 8/15
thes find the value of sinA.cosC+ cosA.sinC​

Answer 1

Answer:

here is the answer sin A× cos c + cos a × sin c

Answer 2

$\fbox\red{given}$

Given a right angled triangle ABC right

angled at B, which tan A = 15/8and

tan c = 8/15 these find the value of sinA.cosC+ cosA.sinC

$\fbox\pink{solution : }$

Since ,the sum of the angles of A triangle is 180° and B is 90° ,A + C is 90°

SinA.cosc + cosA.sinC

= sinA.sin (90° – C) + cosA.cos(90°– C)

= SinA.SinA + CosA.CosA

= sin²A + Cos²A

= 1

$\fbox\green{hence,}$

1.