Question

given a right angled triangle ABC,right angled at C in which tan A= root 3 , tan B=1/root 3, show that the sin A. cos B - cos A .sin b=1/2

Answer 1

Step-by-step explanation:

$\implies AC^2=AB^2+BC^2\\ \implies AC^2=12^2+16^2// \implies AC^2=144+256\\ \implies AC^2=400$

$\boxed{\implies AC=20cm}$

We know that,AO is the radius of the circle.

$\implies AO = \frac{20}{2}$

$\boxed{AO=10cm}$