given a right triangle ABC in which angle b is equal to 90 degree a circle is drawn with ab as diameter intersecting the hypotenuse AC at P prove that tangent to the circle at P bisects BC
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In a right triangle ABC in which∠B = 90º,a circle is drawn with ab as diameter intersecting the hypotenuse AC at P. Prove that the tangent to the circle at P bisect BC. A circle is drawn with AB as diameter intersecting AC in P, PQ is the tangent to the circle which intersects BC at Q.
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