Question

Given a right triangle PQR which is right-angled at Q. QR = 12 cm, PQ = 5 cm. The radius of the circle which is inscribed in triangle PQR will​

Answer 1

let say where the circle is touching the side QP is A and QR will touch at B

and PQ touching at C

then QA = x we assume

then QB=X

BR= 12-X

RC=12-X

CP= 13-12+X

CP=1+X

CP=PA

1+X= 5-X

2X=4

X=2

so radius =2

Answer 2

Answer:

Ra+Ao=12

Rc+CP=13

On+Bp=5

Side Ra= SideRc

LineBp=Line cp