Given a triangle A ( 0,4),B(-4,9) and c (-2,-1) find the equation of altitude through
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Answer:
Given, vertices of a triangle are A(10,4)B(4,−9)andC(−2,−1)
Now,
Slope of line BC(m
1
)=
(−2−4)
(−1+9)
=
(−6)
8
=
3
−4
Let the slope of the altitude from A(10,4) to BC be m
2
Then, m
1
×m
2
=−1
(
3
−4
)×m
2
=−1
m
2
=
4
3
So, the equation of the line will be
y−4=
4
3
(x−10)
4y−16=3x−30
3x−4y−14=0
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