Math, asked by applehoney9721, 1 year ago

Given a triangle and a number n find how many number of ways you can return to the same vertex where you started with total path distance n. Only a fe

Answers

Answered by Anonymous
0
three different array ... Time Complexity: O(N^3) where N is the size of input array. ... And we check for condition (i) when we pick 'k'. 4.
Answered by krithikasmart11
0

Answer:

Input: n = 3

Output: 4

Explanation:

Below are the four ways

1 step + 1 step + 1 step

1 step + 2 step

2 step + 1 step

3 step

Input: n = 4

Output: 7

Explanation:

Below are the four ways

1 step + 1 step + 1 step + 1 step

1 step + 2 step + 1 step

2 step + 1 step + 1 step

1 step + 1 step + 2 step

2 step + 2 step

3 step + 1 step

1 step + 3 step

#SPJ2

Similar questions