given a triangle with side PQ=8CM , to get a line PQ=3/4 of PQ , we divide the line segment PQ in the ratio
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Answered by
2
Step-by-step explanation:
STEPS OF CONSTRUCTION:
1.Draw line segment of length AB=8cm.
2. Draw any Ray AX making acute ∠BAX with AB
3. Draw a parallel to BY parallel to AX by making∠ABY=∠BAX.
4. Make 3 points A
1
,A
2
,A
3
on AX & 4 points B
1
,B
2
,B
3
,B
4
on BY such that
AA
1
=A
1
A
2
=A
2
A
3
=BB
1
=B
1
B
2
=B
2
B
3
=B
3
B
4
5. Join A
3
B
4
. Then it intersect AB at a point P.
Thus P is the point of dividing AB internally in the ratio 3:4.
Answered by
5
Answer:
3:4 íś ans
Step-by-step explanation:
i hope its help to you ✌
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