Given A = {(x, y): 3x-4y = 2}; B =
{(x, y) : x + 6y + 10 = 0). Find An B.
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Thus, a = 2 and b = 4. (2) x + 7y = 10; .....(I) 3x – 2y = 7 .....(II) Multiplying (I ) with 3 3x + 21y = 30; .....(III) 3x – 2y = 7 .....(IV) Subtracting (IV) from (III) we get 23y = 23 ⇒y = 1. Putting the value of y in (IV) we get 3x – 2 = 7
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