Question

Given a year, check if the year is leap year or not. If yes, the output should be “Leap Year”. Else output should be “Not a Leap Year”. The input should be a positive four digit number. Else, the output should be “Invalid Year”.

Answer 1

Answer:

Explanation:

Psuedo code:-

If a year is divisible by 400 -It is leap year. Eg:- 2000

Else If a year is divisible by 100 and NOT 400- It is not leap year Eg:- 1900

Else If a year is divisble by 4 - It is leap year Eg:- 2020

Else it is NOT leap year Eg:- 2019

Program

int main()

{

 int year;

if (year%400 == 0)

   printf("%d Leap Year\n", year);

 else if (year%100 == 0)

   printf("%d Not a Leap Year \n", year);

 else if (year%4 == 0)

   printf("%d Leap Year \n", year);

 else

   printf("%d Not a Leap Year\n", year);  

   

 return 0;

}