Given a12=37 and d=3,find a and s 12 for any A.p
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Answered by
14
if 12 th term is 37
this means that. a+11d=37
d=3
a+11d=37
a+11×3=37
a=37-33
a=4
sum of 12 terms = n/2(a+l)
=12/2(4+37)
=6×41
=246
this means that. a+11d=37
d=3
a+11d=37
a+11×3=37
a=37-33
a=4
sum of 12 terms = n/2(a+l)
=12/2(4+37)
=6×41
=246
Answered by
7
Answer:
S₁₂=246
a=4
Step-by-step explanation:
a₁₂ can be written as a+11d
therefore, a+11d=37
a+33=37
a=4
now S₁₂=n/2[2a+(n-1)d]
=12/2[2(4)+11*3]
=6[8+33]
=6*41
=246
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