Given:a12 =37,d=3,find a and s12
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Answer:
a=4 and S12=246
Step-by-step explanation:
a12=37 , d=3 , n=12
an= a+(n-1)d
a12=a+(12-1)3
37= a+11×3
37=a+33
a=37-33
a=4
Sn=n/2(2a+(n-1)d)
S12=12/2(2×4+(12-1)3)
=6(8+11×3)
=6(8+33)
=6×41
S12 =246
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