given a15= 2a,d=2, find a and s15.
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1
Answer:
a 3 =15,s10 =125
a 3 =a+(3−1)d
15=a+2d
a=15−2d
s 10 = 2/10 [2a+(10−1)d]
125=5[2a+9d]
25=2a+9d
25=2(15−2d)+9d
25=30−4d+9d
5d=−5
d=−1
a=15−2×(−1)
a=17
a 10 =a+(10−1)(−1)
a 10 =17−9
a 10 =26
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